(9/4x^2-1)-(9/4x^2-3x+1)=0

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Solution for (9/4x^2-1)-(9/4x^2-3x+1)=0 equation: 



(9/4x^2-1)-(9/4x^2-3x+1)=0



Domain of the equation: 4x^2-1)!=0

x∈R





Domain of the equation: 4x^2-3x+1)!=0

x∈R



We get rid of parentheses

9/4x^2-9/4x^2+3x-1-1=0

We multiply all the terms by the denominator


3x*4x^2-1*4x^2-1*4x^2+9-9=0

We add all the numbers together, and all the variables

3x*4x^2-1*4x^2-1*4x^2=0

Wy multiply elements

12x^3-4x^2-4x^2=0

We do not support expression: x^3

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